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A382251
a(n) = 7*n^3 - 6*n^2.
1
1, 32, 135, 352, 725, 1296, 2107, 3200, 4617, 6400, 8591, 11232, 14365, 18032, 22275, 27136, 32657, 38880, 45847, 53600, 62181, 71632, 81995, 93312, 105625, 118976, 133407, 148960, 165677, 183600, 202771, 223232, 245025, 268192, 292775, 318816, 346357, 375440, 406107, 438400, 472361
OFFSET
1,2
COMMENTS
Consider a figurate cubic number of the form a(n)=n^3. n is interpreted as the number of dots or nodes in each edge of the cube. Refer this cube as "central cube". Suppose one identical cube is attached to each of its six faces of the central cube. The resulting geometric structure consists of a total of seven arranged cubes so that each of the six surrounding cubes shares an entire face with the central cube. The overlapping dots along these shared faces are counted once. The number of dots in this configuration is given by the formula: a(n) = 7*n^3-6*n^2 for n>=1.
REFERENCES
Jejemae S. Maque, "Augmented Cubic Numbers," Undergraduate Thesis, Bukidnon State University, 2024.
FORMULA
a(n) = 7*n^3 - 6*n^2.
G.f.: x*(1 + 28*x + 13*x^2) / (1-x)^4.
EXAMPLE
For n=2, a(2) = 7*(2^3) - 6*(2^2) = 32.
For n=5, a(5) = 7*(5^3) - 6*(5^2) = 725.
MAPLE
seq(7*n^3 - 6*n^2, n=1..20);
MATHEMATICA
Table[7 n^3 - 6 n^2, {n, 1, 20}]
PROG
(Python)
[7*n**3 - 6*n**2 for n in range(1, 21)]
CROSSREFS
Sequence in context: A044364 A044745 A297641 * A304380 A297887 A298492
KEYWORD
nonn,easy
AUTHOR
Noel B. Lacpao, May 17 2025
STATUS
approved