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Nov 8, 2010 at 7:13 history edited Bernardo Kyotoku CC BY-SA 2.5
added 2 characters in body; added 1 characters in body
Nov 2, 2010 at 20:57 comment added kennytm @Albert: No when the speed of particle is very fast. (p = mv/√(1-v^2/c^2), m is rest mass.)
Nov 2, 2010 at 20:53 comment added Cedric H. "To the extend of my knowledge we don't how to tune up mass." : just by taking another particle
Nov 2, 2010 at 20:25 comment added Albert sorry... I mean p = m * v
Nov 2, 2010 at 20:21 comment added Albert Isn't p = m*c ?
Nov 2, 2010 at 20:18 history answered Bernardo Kyotoku CC BY-SA 2.5