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Rev

$\begingroup$ Very elegant formulation of the problem. I don't know if it would work or not, but the Magnus representation of the propagator might be useful here since the commutators are "nice". $\endgroup$

Mark Mitchison
– Mark Mitchison

2017-01-09 16:03:37 +00:00
Commented Jan 9, 2017 at 16:03
$\begingroup$ Thanks, half-baked unfortunately. The Magnus representation is indeed what one defaults to eventually, but it takes some work. $\endgroup$

udrv
– udrv

2017-01-09 22:39:10 +00:00
Commented Jan 9, 2017 at 22:39

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