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    $\begingroup$ Opposite is true, as the moon pulls the earth as well. See physics.stackexchange.com/q/3534/180843 $\endgroup$ Commented Jan 2, 2024 at 21:15
  • $\begingroup$ I am not sure what do you mean by "pull of its own" $\endgroup$ Commented Jan 2, 2024 at 21:22
  • $\begingroup$ No, as per $ma=GMm/r^2$, falling object acceleration $a$ is independent of object mass, it depends just on interceptor mass $M$. Analogically, Earth falling acceleration towards object is independent on Earth mass, just on object mass. $\endgroup$ Commented Jan 2, 2024 at 21:33
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    $\begingroup$ No, @Agnius. Please see the linked dupe target. $\endgroup$ Commented Jan 2, 2024 at 23:09
  • $\begingroup$ I see. So my suggestion is true just in case $m \ll M$, which is what typical school courses have in mind when describing Newton gravity law. $\endgroup$ Commented Jan 3, 2024 at 7:01