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Jan 19 at 10:56 comment added Bence Racskó @user34722 ... that belongs to the adjoint of the relevant bundle, we multiply with the volume form, e.g. it is the operator $(g^{ij}\partial^2 -\partial^i\partial^j)d^4x$ that should properly be understood in place of what I wrote (note the added $d^4x$), but I omitted this to keep things simple (but somewhat inaccurate).
Jan 19 at 10:50 comment added Bence Racskó @user34722 Added an edit. This link can also be helpful: en.wikipedia.org/wiki/…, but note that since we are working on manifolds, we are not using a scalar product, but rather the $m$-form valued pairing between a bundle and its adjoint. That is needed to ensure the formal adjoint is coordinate-free and doesn't depend on any background structure like a metric. But of course what I did not mention in the answer is that in "free field equations" in order to get an operator ...
Jan 19 at 10:50 history edited Bence Racskó CC BY-SA 4.0
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Jan 19 at 8:27 comment added user34722 This is a bit hard to follow for me since it's in a rather different language/terminology than the original question and what one would typically encounter outside of mathematics/mathematical physics courses. I think I follow everything except for the line where dB appears. What is dB? Do you know what it might be referred to in 'physics language'?
Jan 13 at 8:52 history answered Bence Racskó CC BY-SA 4.0