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Physics

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    $\begingroup$ Well, take $z=x-y$ and you will reduce the "two variables" to just one. $\endgroup$ Commented Aug 1 at 3:11
  • $\begingroup$ If the question about a definition, usually when using operators, one can perform a Fourier transform on them, obtaining polynomes each derivation corresponding to a power of 1 of a Fourier space variable. They can be in nominator or denominator. Thus the differential operation is "possible" to devide by. As for the number of variables, I do not truly undertand your question, since it seems for me that the d'Alambertian depends on the variables $x^\mu$ and inverse one, will also depend on the same coordinates. Why will number of variables change? $\endgroup$ Commented Aug 1 at 12:05
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    $\begingroup$ It's just a sloppy physicist's notation... the equation (3.77) should read $\frac{1}{\square} \delta^{(4)}(x-y)$ $\endgroup$ Commented Aug 1 at 13:27