1
$\begingroup$

It seems that an equation factor must be “squared” as a convenient approximation to balance out some other series of factors invisibly . Might $E=mc^{1.95}$ work as well as $E=mc^2$? Might $A^2+B^2=C^2$ also work if all the factors used the same but different power and be even more accurate? Does anyone know of such a triangle that the current formula comes out to an even number.

$\endgroup$
0

0

Start asking to get answers

Find the answer to your question by asking.

Ask question

Explore related questions

See similar questions with these tags.