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- $\begingroup$ @JLee Checked it just now, yes that is right. $\endgroup$user13180– user131802015-06-14 15:50:27 +00:00Commented Jun 14, 2015 at 15:50
- $\begingroup$ Should condition I be "The first digit is equal to the numerical value of the second character/letter"? $\endgroup$Julian Rosen– Julian Rosen2015-06-14 15:50:38 +00:00Commented Jun 14, 2015 at 15:50
- $\begingroup$ @Julian Ronsen The second character is a letter, from condition E, All the digits are at the end of the password (after the letters). $\endgroup$user13180– user131802015-06-14 15:54:34 +00:00Commented Jun 14, 2015 at 15:54
- 2$\begingroup$ Since the second character is not a number, maybe this should say "the numerical value of the second letter" instead of "the numerical value of the second number" $\endgroup$Julian Rosen– Julian Rosen2015-06-14 15:59:30 +00:00Commented Jun 14, 2015 at 15:59
- 1$\begingroup$ @BitCoder rule K may be ambiguous, when you flip something upside down you can either rotate it 180 degrees or flip over its horizontal axis. Another possible interpretation is that "upside down and mirrored" both refer to the same transformation (e.g. q). Is this solvable as is or should it be clarified? $\endgroup$Quark– Quark2015-06-14 16:15:06 +00:00Commented Jun 14, 2015 at 16:15
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