Timeline for Red, blue and yellow points
Current License: CC BY-SA 3.0
9 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Apr 16, 2016 at 16:14 | vote | accept | Gamow | ||
| Apr 13, 2016 at 17:07 | history | edited | Michael Seifert | CC BY-SA 3.0 | added 483 characters in body |
| Apr 13, 2016 at 13:22 | history | edited | Bolo | CC BY-SA 3.0 | Updated answer, converting to community wiki; Post Made Community Wiki |
| Apr 9, 2016 at 18:57 | comment | added | astralfenix | @BaSzAt Consider that if a >= b and c >= d then a+c >= b+d. This means that if you add the red-blue segments of the first 2 triangles, the result must be no greater than the result of adding the other segments. This can be extended for 3, 4, 5 etc up to all the triangles | |
| Apr 9, 2016 at 18:57 | comment | added | BaSzAt | @ffao I think I understand now. Thanks for clarifying. | |
| Apr 9, 2016 at 18:51 | comment | added | ffao | @BaSzAt If you consider all possible triangles (there are 100 of those, choose one of the reds, the blue and the yellow), then the sum of red-blue and yellow-blue over all triangles is the same: 100. PS: Bolo is too fast, I was about to post the same thing. | |
| Apr 9, 2016 at 18:47 | comment | added | BaSzAt | "The sum of lengths of all the red-blue segments must be no greater than the sum of all lengths of all the red-yellow segments and all the blue-yellow ones." This is not true. Consider 100 red points and one yellow, all in the same place and one blue segment 1 unit away. Then the lengths of red-blue segments add up to 100, while the lengths of yellow-blue and red-yellow ones add up to 1. | |
| Apr 9, 2016 at 18:36 | history | edited | Bolo | CC BY-SA 3.0 | added 78 characters in body |
| Apr 9, 2016 at 18:22 | history | answered | Bolo | CC BY-SA 3.0 |