Timeline for How do I get correct measurement probabilities in ZX calculus?
Current License: CC BY-SA 4.0
6 events
| when toggle format | what | by | license | comment | |
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| Oct 5, 2022 at 0:39 | answer | added | jjgoings | timeline score: 4 | |
| Oct 3, 2022 at 20:30 | comment | added | jjgoings | Yup, seems it needs the extra factors of $\sqrt{2}$ I had left off before. See, e.g., Eq(14) in arxiv.org/abs/2109.01076 | |
| Oct 3, 2022 at 20:20 | comment | added | jjgoings | @CraigGidney Ah, good point! Maybe then the transformation I should have done is represent $|0\rangle$ as $1/\sqrt{2} \times$ leaf node? Likewise for the $\langle 1|$. Then the probabilities should work out in the simple example? | |
| Oct 3, 2022 at 18:03 | comment | added | Craig Gidney | I don't think the scalar value is even supposed to be the probability in the first place? For example, the leaf node on its own has value $\sqrt{2}|0\rangle$ instead of $|0\rangle$ which is not normalized to start with. | |
| S Oct 3, 2022 at 16:38 | review | First questions | |||
| Oct 4, 2022 at 6:11 | |||||
| S Oct 3, 2022 at 16:38 | history | asked | jjgoings | CC BY-SA 4.0 |