Timeline for What does "measuring a state" mean?
Current License: CC BY-SA 4.0
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| Nov 13, 2019 at 19:37 | comment | added | glS♦ | @Upstart I'm not totally clear about the protocol you are proposing but it seems like a probabilistic protocol so no-cloning does not apply in that scenario. Anyway, you might be better off asking that as a separate question as it does not seem to be related to this one. | |
| Nov 13, 2019 at 19:34 | comment | added | Upstart | okay. But can still do what I proposed that I can do a CNOT between the state and my ancilla state $|0\rangle$. And repeat these steps and take the majority measurements. | |
| Nov 13, 2019 at 19:31 | comment | added | glS♦ | @Upstart as per no cloning, you cannot implement a reversible operation duplicating an arbitrary input state. What I'm saying here is simply that in practice you can usually prepare the same state multiple times. Eg shine your laser through the same quantum optical apparatus to alway get the same output. No-cloning has no bearing here because you are not using a state as input to make a copy of the same state | |
| Nov 13, 2019 at 19:27 | comment | added | Upstart | What do you mean when you say take multiple copies?. Can i make i duplicate of that state? But that would violate the no cloning theorem or do I attach an ancilla with my state $\alpha|0\rangle+\beta|1\rangle$ and do a CNOT with that. Do this for say 100 times each time adding an ancilla. After the completion of those 100 rounds the measurement outcome that is in majority is the one my quantum state was in most probably | |
| Nov 13, 2019 at 18:33 | history | answered | glS♦ | CC BY-SA 4.0 |