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Quantum Computing

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    $\begingroup$ Isn't that simply the differential element of the surface - $d\theta\,\sin\theta\,d\phi$, times $1/4\pi$? $\endgroup$ Commented Jan 5, 2020 at 17:08
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    $\begingroup$ What distribution are you drawing your states from? If it's a uniformly distribution over the volume of the Bloch sphere, then the probability is 0. $\endgroup$ Commented Jan 5, 2020 at 17:39
  • $\begingroup$ Yes it might be an uniform distribution, but how can I then compute the POVM $E_{(\theta, \phi)}$? Cause they must satisfy the completeness relation $\int d^\Omega E_{(\theta, \phi)}=\mathbb{I}$ $\endgroup$ Commented Jan 5, 2020 at 18:36
  • $\begingroup$ $dE_{\theta,\phi} = d\theta \sin\theta d\phi/4\pi$. $dE$ is a measure over which you have to integrate. $\endgroup$ Commented Jan 5, 2020 at 22:35
  • $\begingroup$ Where does this question come from? $\endgroup$ Commented Jan 6, 2020 at 10:06