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  • \$\begingroup\$ @doppelgreener, Right! Sorry, I was rolling 3d10 for some of my figures. So here's a proper example. Again, I really appreciate the help! While that will give the proper range, I'm pretty sure it skews the probabilities. For example: d10 + d6 gives me a 1.67% chance of getting an 2, d10 - d6 gives me a 10% chance of getting an 2. Given the mechanic, I've got an 11.67% chance of getting a 2 on any roll. The output you suppied shows a 5.83% chance for it since I'm essentially rolling a custom d12 instead of a d6. \$\endgroup\$ Commented Feb 27, 2017 at 20:09
  • \$\begingroup\$ @MichaelConn Actually, it's right on the money. The odds of getting a 2 with a +d6 are 1.67%, the odds with the -d6 is 10%. The average of those two values is, in fact, 5.835% which is right where it falls with the +/- output. \$\endgroup\$ Commented Feb 27, 2017 at 20:21
  • \$\begingroup\$ @MichaelConn 11.67% divided by two (we've doubled the size of the pool of possibilities) is 5.83%. Also, that custom d12 represents +-d6, which has twelve equally likely possibilities, each one represented on that d12. \$\endgroup\$ Commented Feb 27, 2017 at 20:22
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    \$\begingroup\$ @MichaelConn There are actually 120 combinations since you have the 60 from +d6 and 60 from -d6. So you have 1/60 for +d6 and 6/60 for -d6 \$\endgroup\$ Commented Feb 27, 2017 at 21:29
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    \$\begingroup\$ @MichaelConn Two separate output statements: output 1d10 + 1d6 and output 1d10 - 1d6, then for data type select 'transposed.' Ironically, this was going to be my first answer before I decided it probably wasn't what you're looking for. It won't add the results but it will transpose the data across the results rather than across the outputs, which will allow you to analyze in the way you're looking to. \$\endgroup\$ Commented Feb 27, 2017 at 22:00