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Removed occurences tag as per http://meta.stackoverflow.com/questions/169960/rename-the-occurences-tag
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iDev
iDev
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I'mI am working in a bash shell and I am trying to print only the line of the first occurrence of the string. For example, for the string 'auir', if I have the file myfile.txt and it contains:

123 asdf 4wirajw forauir somethingelse starcraft mylifeforauir auir something else tf.rzauir

I want to output "forauir somethingelse"

So far, I use the command

sed -n '/auir/p' myfile.txt

which gives me all the occurrences of this string. How can I only get the first line that 'auir' occurs on? It'd be great if it was just a single command or pipeline of commands.

Any insight is greatly appreciated.

I'm working in a bash shell and I am trying to print only the line of the first occurrence of the string. For example, for the string 'auir', if I have the file myfile.txt and it contains:

123 asdf 4wirajw forauir somethingelse starcraft mylifeforauir auir something else tf.rzauir

I want to output "forauir somethingelse"

So far, I use the command

sed -n '/auir/p' myfile.txt

which gives me all the occurrences of this string. How can I only get the first line that 'auir' occurs on? It'd be great if it was just a single command or pipeline of commands.

Any insight is greatly appreciated.

I am working in a bash shell and I am trying to print only the line of the first occurrence of the string. For example, for the string 'auir', if I have the file myfile.txt and it contains:

123 asdf 4wirajw forauir somethingelse starcraft mylifeforauir auir something else tf.rzauir

I want to output "forauir somethingelse"

So far, I use the command

sed -n '/auir/p' myfile.txt

which gives me all the occurrences of this string. How can I only get the first line that 'auir' occurs on? It'd be great if it was just a single command or pipeline of commands.

Any insight is greatly appreciated.

formatting
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edit approved May 20, 2012 at 19:00
the paul
edit approved May 20, 2012 at 19:00
the paul
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I'm working in a bash shell and I am trying to print only the line of the first occurrence of the string. For example, for the string 'auir''auir', if I have the file myfile.txt and it contains:

123 asdf 4wirajw forauir somethingelse starcraft mylifeforauir auir something else tf.rzauir

123 asdf 4wirajw forauir somethingelse starcraft mylifeforauir auir something else tf.rzauir

I want to output "forauir somethingelse""forauir somethingelse"

So far, I use the command

sed -n '/auir/p' myfile.txt

sed -n '/auir/p' myfile.txt

which gives me all the occurrences of this string. How can I only get the first line that 'auir''auir' occurs on? It'd be great if it was just a single command or pipeline of commands.

Any insight is greatly appreciated.

I'm working in a bash shell and I am trying to print only the line of the first occurrence of the string. For example, for the string 'auir', if I have the file myfile.txt and it contains:

123 asdf 4wirajw forauir somethingelse starcraft mylifeforauir auir something else tf.rzauir

I want to output "forauir somethingelse"

So far, I use the command

sed -n '/auir/p' myfile.txt

which gives me all the occurrences of this string. How can I only get the first line that 'auir' occurs on? It'd be great if it was just a single command or pipeline of commands.

Any insight is greatly appreciated.

I'm working in a bash shell and I am trying to print only the line of the first occurrence of the string. For example, for the string 'auir', if I have the file myfile.txt and it contains:

123 asdf 4wirajw forauir somethingelse starcraft mylifeforauir auir something else tf.rzauir

I want to output "forauir somethingelse"

So far, I use the command

sed -n '/auir/p' myfile.txt

which gives me all the occurrences of this string. How can I only get the first line that 'auir' occurs on? It'd be great if it was just a single command or pipeline of commands.

Any insight is greatly appreciated.

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Rickster
Rickster
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UNIX: Using egrep or sed to find the line with the first occurrence of a string?

I'm working in a bash shell and I am trying to print only the line of the first occurrence of the string. For example, for the string 'auir', if I have the file myfile.txt and it contains:

123 asdf 4wirajw forauir somethingelse starcraft mylifeforauir auir something else tf.rzauir

I want to output "forauir somethingelse"

So far, I use the command

sed -n '/auir/p' myfile.txt

which gives me all the occurrences of this string. How can I only get the first line that 'auir' occurs on? It'd be great if it was just a single command or pipeline of commands.

Any insight is greatly appreciated.