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After spending about 10 minutes figuring out why it works, that kicks A**! Thanks!

Billy ONeal
– Billy ONeal

2009-07-21 02:18:52 +00:00
Commented Jul 21, 2009 at 2:18
@Charles Bailey, well it took me longer than 10 minutes since my template programming is pretty rusty and I have to agree that it is a very nice and elegant solution. The key is to realize that T(1) will be turned into a value of 1 for the type then the one is shifted so that it will be in the next nibble then subtract 1 to get the 0xf. So an example for unsigned short would be 0x0001 then shifted would be 0x0010 then subtract one to get to 0x000f.

Richard Chambers
– Richard Chambers

2012-09-10 02:56:07 +00:00
Commented Sep 10, 2012 at 2:56

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