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Mechanical snail
Mechanical snail
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The following script generates a C program that solves the problem without using the operators * / + - %:

#!/usr/bin/env python3 print('''#include <stdint.h> #include <stdio.h> const int32_t div_by_3(const int32_t input) { ''') for i in range(-2**322**31, 2**322**31): print(' if(input == %d) return %d;' % (i, i / 3)) print(r''' return 42; // impossible } int main() { const int32_t number = 8; printf("%d / 3 = %d\n", number, div_by_3(number)); } ''')

The following script generates a C program that solves the problem without using the operators * / + - %:

#!/usr/bin/env python3 print('''#include <stdint.h> #include <stdio.h> const int32_t div_by_3(const int32_t input) { ''') for i in range(-2**32, 2**32): print(' if(input == %d) return %d;' % (i, i / 3)) print(r''' return 42; // impossible } int main() { const int32_t number = 8; printf("%d / 3 = %d\n", number, div_by_3(number)); } ''')

The following script generates a C program that solves the problem without using the operators * / + - %:

#!/usr/bin/env python3 print('''#include <stdint.h> #include <stdio.h> const int32_t div_by_3(const int32_t input) { ''') for i in range(-2**31, 2**31): print(' if(input == %d) return %d;' % (i, i / 3)) print(r''' return 42; // impossible } int main() { const int32_t number = 8; printf("%d / 3 = %d\n", number, div_by_3(number)); } ''')
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Mechanical snail
Mechanical snail
  • 30.7k
  • 15
  • 91
  • 113

The following script generates a C program that solves the problem without using the operators * / + - %:

#!/usr/bin/env python3 print('''#include <stdint.h> #include <stdio.h> const int32_t div_by_3(const int32_t input) { ''') for i in range(-2**32, 2**32): print(' if(input == %d) return %d;' % (i, i / 3)) print(r''' return 42; // impossible } int main() { const int32_t number = 8; printf("%d / 3 = %d\n", number, div_by_3(number)); } ''')
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