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Explore Stack Internal iI think this is handled by the compiler. ifIf you open the .net.net assembly in ILDASMILDASM you will see the default constructor, even if it is not in the code. If you define a parameterized constructor the default constructor will not bee seen.
actuallyActually when you define the class (non static), the compiler provides this feature thinking that you will be just creating an instance. And if you want any specific operation to perform you surely will be having your own constructor.
i think this is handled by the compiler. if you open the .net assembly in ILDASM you will see the default constructor, even if it is not in the code. If you define a parameterized constructor the default constructor will not bee seen.
actually when you define the class (non static), the compiler provides this feature thinking that you will be just creating an instance. And if you want any specific operation to perform you surely will be having your own constructor.
I think this is handled by the compiler. If you open the .net assembly in ILDASM you will see the default constructor, even if it is not in the code. If you define a parameterized constructor the default constructor will not bee seen.
Actually when you define the class (non static), the compiler provides this feature thinking that you will be just creating an instance. And if you want any specific operation to perform you surely will be having your own constructor.
i think this is handled by the compiler. if you open the .net assembly in ILDASM you will see the default constructor, even if it is not in the code. If you define a parameterized constructor the default constructor will not bee seen.
actually when you define the class (non static), the compiler provides this feature thinking that you will be just creating an instance. And if you want any specific operation to perform you surely will be having your own constructor.
