Revisions to How can I replace each newline (\n) with a space using sed?

Add shell syntax highlighting

edited Oct 18 at 18:23

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The Perl version works the way you expected.

perl -i -p -e 's/\n//' file

perl -i -p -e 's/\n//' file

As pointed out in the comments, it's worth noting that this edits in place. -i.bak will give you a backup of the original file before the replacement in case your regular expression isn't as smart as you thought.

The Perl version works the way you expected.

perl -i -p -e 's/\n//' file

As pointed out in the comments, it's worth noting that this edits in place. -i.bak will give you a backup of the original file before the replacement in case your regular expression isn't as smart as you thought.

The Perl version works the way you expected.

perl -i -p -e 's/\n//' file

As pointed out in the comments, it's worth noting that this edits in place. -i.bak will give you a backup of the original file before the replacement in case your regular expression isn't as smart as you thought.

Copy edited. Added some context. Removed historical information (e.g. ref. <http://meta.stackexchange.com/a/230693> and <http://meta.stackoverflow.com/questions/266164>).

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edited Mar 31, 2015 at 8:09

Peter Mortensen

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The perlPerl version works the way you expected.

perl -i -p -e 's/\n//' file

Edit: As pointed out in the comments, it's worth noting that this edits in place. -i.bak will give you a backup of the original file before the replacement in case your regexregular expression isn't as smart as you thought.

The perl version works the way you expected.

perl -i -p -e 's/\n//' file

Edit: As pointed out in the comments, it's worth noting that this edits in place. -i.bak will give you a backup of the original file before the replacement in case your regex isn't as smart as you thought.

The Perl version works the way you expected.

perl -i -p -e 's/\n//' file

As pointed out in the comments, it's worth noting that this edits in place. -i.bak will give you a backup of the original file before the replacement in case your regular expression isn't as smart as you thought.

Added -i.bak info

Source Link

edited Aug 10, 2009 at 13:52

ire_and_curses

70.6k
24
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The perl version works the way you expected.

perl -i -p -e 's/\n//' file

Edit: As pointed out in the comments, it's worth noting that this edits in place. -i.bak will give you a backup of the original file before the replacement in case your regex isn't as smart as you thought.

The perl version works the way you expected.

perl -i -p -e 's/\n//' file

The perl version works the way you expected.

perl -i -p -e 's/\n//' file

Edit: As pointed out in the comments, it's worth noting that this edits in place. -i.bak will give you a backup of the original file before the replacement in case your regex isn't as smart as you thought.

Source Link

answered Aug 9, 2009 at 19:25

ire_and_curses

70.6k
24
120
141

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