Revisions to How to manage a redirect request after a jQuery Ajax call

corrected typo

edited Oct 17, 2008 at 0:50

Use the low-level $.ajax() call:

$.ajax({ url: "/yourservlet", data: { }, complete: function(xmlHttp) { // xmlHttp is a XMLHttpRquest object alert(xmlHttp.codestatus); } });

Try this for a redirect:

if (xmlHttp.code != 200) { top.location.href = '/some/other/page'; }

Use the low-level $.ajax() call:

$.ajax({ url: "/yourservlet", data: { }, complete: function(xmlHttp) { // xmlHttp is a XMLHttpRquest object alert(xmlHttp.code); } });

Try this for a redirect:

if (xmlHttp.code != 200) { top.location.href = '/some/other/page'; }

Use the low-level $.ajax() call:

$.ajax({ url: "/yourservlet", data: { }, complete: function(xmlHttp) { // xmlHttp is a XMLHttpRquest object alert(xmlHttp.status); } });

Try this for a redirect:

if (xmlHttp.code != 200) { top.location.href = '/some/other/page'; }

Extended answer

edited Oct 14, 2008 at 13:30

Use the low-level $.ajax() call:

$.ajax({ url: "/yourservlet", data: { }, complete: function(xmlHttp) { // xmlHttp is a XMLHttpRquest object alert(xmlHttp.code); } });

Try this for a redirect:

if (xmlHttp.code != 200) { top.location.href = '/some/other/page'; }

Use the low-level $.ajax() call:

$.ajax({ url: "/yourservlet", data: { }, complete: function(xmlHttp) { // xmlHttp is a XMLHttpRquest object alert(xmlHttp.code); } });

Use the low-level $.ajax() call:

$.ajax({ url: "/yourservlet", data: { }, complete: function(xmlHttp) { // xmlHttp is a XMLHttpRquest object alert(xmlHttp.code); } });

Try this for a redirect:

if (xmlHttp.code != 200) { top.location.href = '/some/other/page'; }

answered Oct 13, 2008 at 21:54

Use the low-level $.ajax() call:

$.ajax({ url: "/yourservlet", data: { }, complete: function(xmlHttp) { // xmlHttp is a XMLHttpRquest object alert(xmlHttp.code); } });

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