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Rakete1111
Rakete1111
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g++: how How to specify preference of library path?

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Ciro Santilli OurBigBook.com
Ciro Santilli OurBigBook.com
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I'm compiling a c++ program using g++ and ld. I have a .so library I want to be used during linking. However, a library of the same name exists in /usr/local/lib, and ld is choosing that library over the one I'm directly specifying. How can I fix this?

For the examples below, my library file is /my/dir/libfoo.so.0. Things I've tried that don't work:

  • my g++ command is g++ -g -Wall -o my_binary -L/my/dir -lfoo bar.cpp
  • adding /my/dir to the beginning or end of my $PATH en` variable
  • adding /my/dir/libfoo.so.0 as an argument to g++

Thanks.

I'm compiling a c++ program using g++ and ld. I have a .so library I want to be used during linking. However, a library of the same name exists in /usr/local/lib, and ld is choosing that library over the one I'm directly specifying. How can I fix this?

For the examples below, my library file is /my/dir/libfoo.so.0. Things I've tried that don't work:

  • my g++ command is g++ -g -Wall -o my_binary -L/my/dir -lfoo bar.cpp
  • adding /my/dir to the beginning or end of my $PATH en` variable
  • adding /my/dir/libfoo.so.0 as an argument to g++

Thanks.

I'm compiling a c++ program using g++ and ld. I have a .so library I want to be used during linking. However, a library of the same name exists in /usr/local/lib, and ld is choosing that library over the one I'm directly specifying. How can I fix this?

For the examples below, my library file is /my/dir/libfoo.so.0. Things I've tried that don't work:

  • my g++ command is g++ -g -Wall -o my_binary -L/my/dir -lfoo bar.cpp
  • adding /my/dir to the beginning or end of my $PATH en` variable
  • adding /my/dir/libfoo.so.0 as an argument to g++
popular question might deserve better formatting (code sections)
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edit approved Sep 9, 2014 at 16:34
Sebastian
edit approved Sep 9, 2014 at 16:34
Sebastian
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I'm compiling a c++ program using g++g++ and ldld. I have a .so.so library I want to be used during linking. However, a library of the same name exists in /usr/local/lib/usr/local/lib, and ldld is choosing that library over the one I'm directly specifying. How can I fix this?

For the examples below, my library file is /my/dir/libfoo.so.0/my/dir/libfoo.so.0. Things I've tried that don't work:

  • my g++ command is "g++ -g -Wall -o my_binary -L/my/dir -lfoo bar.cpp"g++ -g -Wall -o my_binary -L/my/dir -lfoo bar.cpp
  • adding /my/dir/my/dir to the beginning or end of my $PATH env$PATH en` variable
  • adding /my/dir/libfoo.so.0/my/dir/libfoo.so.0 as an argument to g++

Thanks.

I'm compiling a c++ program using g++ and ld. I have a .so library I want to be used during linking. However, a library of the same name exists in /usr/local/lib, and ld is choosing that library over the one I'm directly specifying. How can I fix this?

For the examples below, my library file is /my/dir/libfoo.so.0. Things I've tried that don't work:

  • my g++ command is "g++ -g -Wall -o my_binary -L/my/dir -lfoo bar.cpp"
  • adding /my/dir to the beginning or end of my $PATH env variable
  • adding /my/dir/libfoo.so.0 as an argument to g++

Thanks.

I'm compiling a c++ program using g++ and ld. I have a .so library I want to be used during linking. However, a library of the same name exists in /usr/local/lib, and ld is choosing that library over the one I'm directly specifying. How can I fix this?

For the examples below, my library file is /my/dir/libfoo.so.0. Things I've tried that don't work:

  • my g++ command is g++ -g -Wall -o my_binary -L/my/dir -lfoo bar.cpp
  • adding /my/dir to the beginning or end of my $PATH en` variable
  • adding /my/dir/libfoo.so.0 as an argument to g++

Thanks.

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Heinrich Schmetterling
Heinrich Schmetterling
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