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There's no out of bounds access or UB in your example.

P.P
– P.P

2015-06-17 05:53:46 +00:00
Commented Jun 17, 2015 at 5:53
@BlueMoon Wanted to show some array out of bound access and end up writing in-bound access code :)

Gopi
– Gopi

2015-06-17 06:00:52 +00:00
Commented Jun 17, 2015 at 6:00
3

char a[3] = "string"; isn't a run-time buffer overflow, it's a constraint violation that will be detected at compile time. N1570 6.7.9p2: "No initializer shall attempt to provide a value for an object not contained within the entity being initialized."

Keith Thompson
– Keith Thompson

2015-06-17 06:02:07 +00:00
Commented Jun 17, 2015 at 6:02
@KeithThompson yeah I get it

Gopi
– Gopi

2015-06-17 06:03:37 +00:00
Commented Jun 17, 2015 at 6:03
@KeithThompson Yeah I made my point clear by showing out of bound access which should be good

Gopi
– Gopi

2015-06-17 06:12:50 +00:00
Commented Jun 17, 2015 at 6:12

| Show 2 more comments

Correct minor typos or mistakes
Clarify meaning without changing it
Add related resources or links
Always respect the author’s intent
Don’t use edits to reply to the author

create code fences with backticks ` or tildes ~
```
like so
```
add language identifier to highlight code
```python
def function(foo):
print(foo)
```
put returns between paragraphs
for linebreak add 2 spaces at end
_italic_ or **bold**
indent code by 4 spaces
backtick escapes `like _so_`
quote by placing > at start of line
to make links (use https whenever possible)

<https://example.com>

[example](https://example.com)

<a href="https://example.com">example</a>

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