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- Omitting the const on the member functions was unintentional, though I'm not sure if it impacts the ill-formedness (or otherwise) of the examples. I've added const just in case.Andrew Tomazos– Andrew Tomazos2015-09-27 04:08:43 +00:00Commented Sep 27, 2015 at 4:08
- I've also changed the default constructed S to be a local variable in the second example, for clarity.Andrew Tomazos– Andrew Tomazos2015-09-27 04:09:36 +00:00Commented Sep 27, 2015 at 4:09
- I'm not 100% myself, however, it only invokes the semantic issue that the function obviously operates as const, but isn't (or wasn't) declared const, and so would generate an error if an S were passed as a const & S or similar from which f() was called. I actually thought you were testing US out here ;)JVene– JVene2015-09-27 04:10:37 +00:00Commented Sep 27, 2015 at 4:10
- Yes, and that doesn't happen in the examples, so why I don't think it effects the answer.Andrew Tomazos– Andrew Tomazos2015-09-27 04:11:51 +00:00Commented Sep 27, 2015 at 4:11
- I'm also unclear as to your answer. You say it fails based on semantic rules? To which semantic rules are you refering?Andrew Tomazos– Andrew Tomazos2015-09-27 04:12:32 +00:00Commented Sep 27, 2015 at 4:12
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