Find centralized, trusted content and collaborate around the technologies you use most.
Learn more about CollectivesStack Internal
Knowledge at work
Bring the best of human thought and AI automation together at your work.
Explore Stack InternalThis is the code I have for measuring how long it took the user to complete the program:
start_time = time.time() # Sits at the top of my code print("%f seconds" % (time.time() - start_time)) # Goes at the bottom of my code My question is, how do I round the output of this to one decimal place? For example, if my output was 3.859639 seconds how would I present this like: 3.48 Secounds?
This is the code I have for measuring how long it took the user to complete the program:
start_time = time.time() # Sits at the top of my code print("%f seconds" % (time.time() - start_time)) # Goes at the bottom of my code My question is, how do I round the output of this to one decimal place? For example, if my output was 3.859639 seconds how would I present this like: 3.4 Secounds?
This is the code I have for measuring how long it took the user to complete the program:
start_time = time.time() # Sits at the top of my code print("%f seconds" % (time.time() - start_time)) # Goes at the bottom of my code My question is, how do I round the output of this to one decimal place? For example, if my output was 3.859639 seconds how would I present this like: 3.8 Secounds?
This is the code I have for measuring how long it took the user to complete the program: start_time = time.time() # Sits at the top of my code print("%f seconds" % (time.time() - start_time)) # Goes at the bottom of my code
start_time = time.time() # Sits at the top of my code print("%f seconds" % (time.time() - start_time)) # Goes at the bottom of my code My question is, how do I round the output of this to one decimal place? For example, if my output was 3.859639 seconds how would I present this like: 3.4 Secounds?
This is the code I have for measuring how long it took the user to complete the program: start_time = time.time() # Sits at the top of my code print("%f seconds" % (time.time() - start_time)) # Goes at the bottom of my code
My question is, how do I round the output of this to one decimal place? For example, if my output was 3.859639 seconds how would I present this like: 3.4 Secounds?
This is the code I have for measuring how long it took the user to complete the program:
start_time = time.time() # Sits at the top of my code print("%f seconds" % (time.time() - start_time)) # Goes at the bottom of my code My question is, how do I round the output of this to one decimal place? For example, if my output was 3.859639 seconds how would I present this like: 3.4 Secounds?
This is the code I have for measuring how long it took the user to complete the program: start_time = time.time() # Sits at the top of my code print("%f seconds" % (time.time() - start_time)) # Goes at the bottom of my code
My question is, how do I round the output of this to one decimal place? For example, if my output was 3.859639 seconds how would I present this like: 3.4 Secounds?