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Explore Stack InternalYou can easily write a function that applies multiple arguments to such a curried function:
const applyuncurry = fn => (...args) => args.reduce((f, x) => f(x), fn); // or alternatively: const applyuncurry = fn => (...args) => { let f = fn; for (const x of args) f = f(x); return f; } Now you can invoke add like so:
applyuncurry(add)(2, 3, 4) and if you still hate that you could also use
const $ = applyuncurry(applyuncurry); $(add, 2, 3, 4) You can easily write a function that applies multiple arguments to such a curried function:
const apply = fn => (...args) => args.reduce((f, x) => f(x), fn); // or alternatively: const apply = fn => (...args) => { let f = fn; for (const x of args) f = f(x); return f; } Now you can invoke add like so:
apply(add)(2, 3, 4) and if you still hate that you could also use
const $ = apply(apply); $(add, 2, 3, 4) You can easily write a function that applies multiple arguments to such a curried function:
const uncurry = fn => (...args) => args.reduce((f, x) => f(x), fn); // or alternatively: const uncurry = fn => (...args) => { let f = fn; for (const x of args) f = f(x); return f; } Now you can invoke add like so:
uncurry(add)(2, 3, 4) and if you still hate that you could also use
const $ = uncurry(uncurry); $(add, 2, 3, 4) You can easily write a function that applies multiple arguments to such a curried function:
const apply = ffn => (...args) => args.reduce((f, x) => f(x), ffn); // or alternatively: const apply = ffn => (...args) => { let f = fn; for (letconst x of args) f = f(x); return f; } Now you can invoke add like so:
apply(add)(2, 3, 4) and if you still hate that you could also use
const $ = apply(apply); $(add, 2, 3, 4) You can easily write a function that applies multiple arguments to such a curried function:
const apply = f => (...args) => args.reduce((f, x) => f(x), f); // or alternatively: const apply = f => (...args) => { for (let x of args) f = f(x); return f; } Now you can invoke add like so:
apply(add)(2, 3, 4) and if you still hate that you could also use
const $ = apply(apply); $(add, 2, 3, 4) You can easily write a function that applies multiple arguments to such a curried function:
const apply = fn => (...args) => args.reduce((f, x) => f(x), fn); // or alternatively: const apply = fn => (...args) => { let f = fn; for (const x of args) f = f(x); return f; } Now you can invoke add like so:
apply(add)(2, 3, 4) and if you still hate that you could also use
const $ = apply(apply); $(add, 2, 3, 4) You can easily write a function that applies multiple arguments to such a curried function:
const apply = f => (...args) => args.reduce((f, x) => f(x), f); // or alternatively: const apply = f => (...args) => { for (let x of args) f = f(x); return f; } Now you can invoke add like so:
apply(add)(2, 3, 4) and if you still hate that you could also use
const $ = apply(apply); $(add, 2, 3, 4) You can easily write a function that applies multiple arguments to such a curried function:
const apply = f => (...args) => args.reduce((f, x) => f(x), f); // or alternatively: const apply = f => (...args) => { for (let x of args) f = f(x); return f; } Now you can invoke add like so:
apply(add)(2, 3, 4) You can easily write a function that applies multiple arguments to such a curried function:
const apply = f => (...args) => args.reduce((f, x) => f(x), f); // or alternatively: const apply = f => (...args) => { for (let x of args) f = f(x); return f; } Now you can invoke add like so:
apply(add)(2, 3, 4) and if you still hate that you could also use
const $ = apply(apply); $(add, 2, 3, 4)