Revisions to How to read a value from an absolute address through C code

fist -> first

edited Jan 23, 2022 at 21:23

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Two ways:

1. Cast the address literal as a pointer:

char value = *(char*)0xff73000;

Cast the literal as a pointer to the type.

and

De-reference using the prefix *.

Same technique applies also to other types.

2. Assign the address to a pointer:

char* pointer = (char*)0xff73000;

Then access the value:

char value = *pointer; char fist_bytefirst_byte = pointer[0]; char second_byte = pointer[1];

Where char is the type your address represents.

Two ways:

1. Cast the address literal as a pointer:

char value = *(char*)0xff73000;

Cast the literal as a pointer to the type.

and

De-reference using the prefix *.

Same technique applies also to other types.

2. Assign the address to a pointer:

char* pointer = (char*)0xff73000;

Then access the value:

char value = *pointer; char fist_byte = pointer[0]; char second_byte = pointer[1];

Where char is the type your address represents.

Two ways:

1. Cast the address literal as a pointer:

char value = *(char*)0xff73000;

Cast the literal as a pointer to the type.

and

De-reference using the prefix *.

Same technique applies also to other types.

2. Assign the address to a pointer:

char* pointer = (char*)0xff73000;

Then access the value:

char value = *pointer; char first_byte = pointer[0]; char second_byte = pointer[1];

Where char is the type your address represents.

Method A is very clear and succinct. Added a few short explanations so it may be more apparent.

Source Link

edit approved May 23, 2021 at 12:51

coarist

888
12
11

Two ways:

1. Cast the address literal as a pointer:

char value = *(char*)0xff73000;

Cast the literal as a pointer to the type.

and

De-reference using the prefix *.

Same technique applies also to other types.

2. Assign the address to a pointer:

char* pointer = (char*)0xff73000;

Then access the value:

char value = *pointer; char fist_byte = pointer[0]; char second_byte = pointer[1];

Where char is the type your address represents.

Two ways:

1. Cast the address literal as a pointer:

char value = *(char*)0xff73000;

2. Assign the address to a pointer:

char* pointer = (char*)0xff73000;

Then access the value:

char value = *pointer; char fist_byte = pointer[0]; char second_byte = pointer[1];

Where char is the type your address represents.

Two ways:

1. Cast the address literal as a pointer:

char value = *(char*)0xff73000;

Cast the literal as a pointer to the type.

and

De-reference using the prefix *.

Same technique applies also to other types.

2. Assign the address to a pointer:

char* pointer = (char*)0xff73000;

Then access the value:

char value = *pointer; char fist_byte = pointer[0]; char second_byte = pointer[1];

Where char is the type your address represents.

implicit conversion from int to char* is illegal in C.

Source Link

edited Oct 25, 2020 at 5:07

Peter Cordes

376.9k
50
742
1k

Two ways:

1. Cast the address literal as a pointer:

char value = *(char*)0xff73000;

2. Assign the address to a pointer:

char* pointer = (char*)0xff73000;

Then access the value:

char value = *pointer; char fist_byte = pointer[0]; char second_byte = pointer[1];

Where char is the type your address represents.

Two ways:

1. Cast the address literal as a pointer:

char value = *(char*)0xff73000;

2. Assign the address to a pointer:

char* pointer = 0xff73000;

Then access the value:

char value = *pointer; char fist_byte = pointer[0]; char second_byte = pointer[1];

Where char is the type your address represents.

Two ways:

1. Cast the address literal as a pointer:

char value = *(char*)0xff73000;

2. Assign the address to a pointer:

char* pointer = (char*)0xff73000;

Then access the value:

char value = *pointer; char fist_byte = pointer[0]; char second_byte = pointer[1];

Where char is the type your address represents.

Source Link

answered Mar 24, 2016 at 13:51

Zdeněk Gromnica

883
2
15
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