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No problem. btw, if muhuk is right and it's a list of Django objects, you should consider his solution. However, for the general case of sorting objects, my solution is probably best practice.

Kenan Banks
– Kenan Banks

2008-12-31 17:12:38 +00:00
Commented Dec 31, 2008 at 17:12
70

On large lists you will get better performance using operator.attrgetter('count') as your key. This is just an optimized (lower level) form of the lambda function in this answer.

David Eyk
– David Eyk

2008-12-31 19:35:24 +00:00
Commented Dec 31, 2008 at 19:35
8

Thanks for the great answer. In case if it is a list of dictionaries and 'count' is one of its key then it needs to be changed like below : ut.sort(key=lambda x: x['count'], reverse=True)

dganesh2002
– dganesh2002

2016-12-08 21:20:13 +00:00
Commented Dec 8, 2016 at 21:20
2

I suppose it deserves the following update: if there is a need to sort by multiple fields, it could be achieved by consecutive calls to sort(), because python is using stable sort algorithm.

uuu777
– uuu777

2020-02-23 14:41:02 +00:00
Commented Feb 23, 2020 at 14:41
2

Thanks @KenanBanks, you were right. Annoyingly outlook was doing some weird things with calendar timezones so that some came through without the timezone details... no idea why!

peetysmith
– peetysmith

2022-04-20 06:05:55 +00:00
Commented Apr 20, 2022 at 6:05

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