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In numpy, index and dimension numbering starts with 0. So axis 0 means the 1st dimension. Also in numpy a dimension can have length (size) 0. The simplest case is:

In [435]: x = np.zeros((0,), int) In [436]: x Out[436]: array([], dtype=int32) In [437]: x[0] ... IndexError: index 0 is out of bounds for axis 0 with size 0 

I also get it if x = np.zeros((0,5), int), a 2d array with 0 rows, and 5 columns.

So someplace in your code you are creating an array with a size 0 first axis.

When asking about errors, it is expected that you tell us where the error occurs.

Also when debugging problems like this, the first thing you should do is print the shape (and maybe the dtype) of the suspected variables.

Applied to pandas

• The same error can occur for those using pandas, when sending a Series or DataFrame to a numpy.array, as with the following:
  • pandas.Series.values or pandas.Series.to_numpy() or pandas.Series.array
  • pandas.DataFrame.values or pandas.DataFrame.to_numpy()

In numpy, index and dimension numbering starts with 0. So axis 0 means the 1st dimension. Also in numpy a dimension can have length (size) 0. The simplest case is:

In [435]: x = np.zeros((0,), int) In [436]: x Out[436]: array([], dtype=int32) In [437]: x[0] ... IndexError: index 0 is out of bounds for axis 0 with size 0 

I also get it if x = np.zeros((0,5), int), a 2d array with 0 rows, and 5 columns.

So someplace in your code you are creating an array with a size 0 first axis.

When asking about errors, it is expected that you tell us where the error occurs.

Also when debugging problems like this, the first thing you should do is print the shape (and maybe the dtype) of the suspected variables.

Applied to pandas

• The same error can occur for those using pandas, when sending a Series or DataFrame to a numpy.array, as with the following:
  • pandas.Series.values or pandas.Series.to_numpy() or pandas.Series.array
  • pandas.DataFrame.values or pandas.DataFrame.to_numpy()

Resolving the error:

1. Use a try-except block
2. Verify the size of the array is not 0
   • if x.size != 0:

In numpy, index and dimension numbering starts with 0. So axis 0 means the 1st dimension. Also in numpy a dimension can have length (size) 0. The simplest case is:

In [435]: x = np.zeros((0,), int) In [436]: x Out[436]: array([], dtype=int32) In [437]: x[0] ... IndexError: index 0 is out of bounds for axis 0 with size 0 

I also get it if x = np.zeros((0,5), int), a 2d array with 0 rows, and 5 columns.

So someplace in your code you are creating an array with a size 0 first axis.

When asking about errors, it is expected that you tell us where the error occurs.

Also when debugging problems like this, the first thing you should do is print the shape (and maybe the dtype) of the suspected variables.

Applied to pandas

• The same error can occur for those using pandas, when sending a Series or DataFrame to a numpy.array, as with the following:
  • pandas.Series.values or pandas.Series.to_numpy()
  • pandas.DataFrame.values or pandas.DataFrame.to_numpy()

In numpy, index and dimension numbering starts with 0. So axis 0 means the 1st dimension. Also in numpy a dimension can have length (size) 0. The simplest case is:

In [435]: x = np.zeros((0,), int) In [436]: x Out[436]: array([], dtype=int32) In [437]: x[0] ... IndexError: index 0 is out of bounds for axis 0 with size 0 

I also get it if x = np.zeros((0,5), int), a 2d array with 0 rows, and 5 columns.

So someplace in your code you are creating an array with a size 0 first axis.

When asking about errors, it is expected that you tell us where the error occurs.

Also when debugging problems like this, the first thing you should do is print the shape (and maybe the dtype) of the suspected variables.

Applied to pandas

• The same error can occur for those using pandas, when sending a Series or DataFrame to a numpy.array, as with the following:
  • pandas.Series.values or pandas.Series.to_numpy() or pandas.Series.array
  • pandas.DataFrame.values or pandas.DataFrame.to_numpy()

In numpy, index and dimension numbering starts with 0. So axis 0 means the 1st dimension. Also in numpy a dimension can have length (size) 0. The simplest case is:

In [435]: x = np.zeros((0,), int) In [436]: x Out[436]: array([], dtype=int32) In [437]: x[0] ... IndexError: index 0 is out of bounds for axis 0 with size 0 

I also get it if x = np.zeros((0,5), int), a 2d array with 0 rows, and 5 columns.

So someplace in your code you are creating an array with a size 0 first axis.

When asking about errors, it is expected that you tell us where the error occurs.

Also when debugging problems like this, the first thing you should do is print the shape (and maybe the dtype) of the suspected variables.

In numpy, index and dimension numbering starts with 0. So axis 0 means the 1st dimension. Also in numpy a dimension can have length (size) 0. The simplest case is:

In [435]: x = np.zeros((0,), int) In [436]: x Out[436]: array([], dtype=int32) In [437]: x[0] ... IndexError: index 0 is out of bounds for axis 0 with size 0 

I also get it if x = np.zeros((0,5), int), a 2d array with 0 rows, and 5 columns.

So someplace in your code you are creating an array with a size 0 first axis.

When asking about errors, it is expected that you tell us where the error occurs.

Also when debugging problems like this, the first thing you should do is print the shape (and maybe the dtype) of the suspected variables.

Applied to pandas

• The same error can occur for those using pandas, when sending a Series or DataFrame to a numpy.array, as with the following:
  • pandas.Series.values or pandas.Series.to_numpy()
  • pandas.DataFrame.values or pandas.DataFrame.to_numpy()