Timeline for answer to How to wait in bash for several subprocesses to finish, and return exit code !=0 when any subprocess ends with code !=0? by Alexander Mills
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| when toggle format | what | by | license | comment | |
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| Sep 30, 2024 at 6:15 | comment | added | Zug | On my computer, the output of `jobs -p` is empty (no job for the subshell related to the backticks, I guess). Moreover it triggers SIGCHLD, which is not what we want, right? | |
| Dec 14, 2017 at 23:20 | history | edited | Alexander Mills | CC BY-SA 3.0 | added 191 characters in body |
| Jul 7, 2017 at 20:12 | comment | added | Alexander Mills | you absolutely sure about that? Not sure if that makes sense. | |
| Jul 7, 2017 at 20:11 | comment | added | inetknght | trap $? $$ seems to set exit code to 0 and PID to current running bash shell, every time for me | |
| Feb 13, 2017 at 10:41 | history | answered | Alexander Mills | CC BY-SA 3.0 |