public class SuperClass { public void method1() { System.out.println("superclass method1"); this.method2(); } public void method2() { System.out.println("superclass method2"); } } public class SubClass extends SuperClass { @Override public void method1() { System.out.println("subclass method1"); super.method1(); } @Override public void method2() { System.out.println("subclass method2"); } } public class Demo { public static void main(String[] args) { SubClass mSubClass = new SubClass(); mSubClass.method1(); } } 

my expected output: subclass method1 superclass method1 superclass method2

actual output: subclass method1 superclass method1 subclass method2

I know technically I have overriden a public method, but I figured that because I was calling the super, any calls within the super would stay in the super, this isn't happening. Any ideas as to how I can make it happen?

public class SuperClass { public void method1() { System.out.println("superclass method1"); this.method2(); } public void method2() { System.out.println("superclass method2"); } } public class SubClass extends SuperClass { @Override public void method1() { System.out.println("subclass method1"); super.method1(); } @Override public void method2() { System.out.println("subclass method2"); } } public class Demo { public static void main(String[] args) { SubClass mSubClass = new SubClass(); mSubClass.method1(); } } 

my expected output:

subclass method1
superclass method1
superclass method2

actual output:

subclass method1
superclass method1
subclass method2

I know technically I have overriden a public method, but I figured that because I was calling the super, any calls within the super would stay in the super, this isn't happening. Any ideas as to how I can make it happen?

public Class SuperClass { public void method1() { System.out.println("superclass method1"); this.method2(); } public void method2() { System.out.println("superclass method2"); } } public Class SubClass extends SuperClass { @Override public void method1() { System.out.println("subclass method1"); super.method1(); } @Override public void method2() { System.out.println("subclass method2"); } } public class Demo { public static void main(String[] args) { SubClass mSubClass = new SubClass(); mSubClass.method1(); } } 

my expected output: subclass method1 superclass method1 superclass method2

actual output: subclass method1 superclass method1 subclass method2

I know technically I have overriden a public method, but I figured that because I was calling the super, any calls within the super would stay in the super, this isn't happening. Any ideas as to how I can make it happen?

public class SuperClass { public void method1() { System.out.println("superclass method1"); this.method2(); } public void method2() { System.out.println("superclass method2"); } } public class SubClass extends SuperClass { @Override public void method1() { System.out.println("subclass method1"); super.method1(); } @Override public void method2() { System.out.println("subclass method2"); } } public class Demo { public static void main(String[] args) { SubClass mSubClass = new SubClass(); mSubClass.method1(); } } 

my expected output: subclass method1 superclass method1 superclass method2

actual output: subclass method1 superclass method1 subclass method2

I know technically I have overriden a public method, but I figured that because I was calling the super, any calls within the super would stay in the super, this isn't happening. Any ideas as to how I can make it happen?