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lang-js
['one'].concat(parts, ['two', 'three'])(or['one'].concat(parts).concat(['two', 'three'])if you don't want to pass multiple arguments).concat(x)makes the reader assume thatxis an array as well. Sure,concatcan handle non-array values as well, but imo that's not its main mode of operation. Especially ifxis an arbitrary (unknown) value, you would need to write.concat([x])to make sure it always works as intended. And as soon as you have to write an array literal anyway, I say that you should just use spread syntax instead ofconcat.