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fix logic error

edited Mar 15, 2013 at 15:12

A more "awk-ish" way to write smcameron's answer:

awk 'NR-v n=5 '1; NR % 5n == 0 {print ""} 1' myfile'

The trailing "1""1;" is a condition that is always true, and will trigger the default action which is to print the current line.

A more "awk-ish" way to write smcameron's answer:

awk 'NR % 5 == 0 {print ""} 1' myfile

The trailing "1" is a condition that is always true, and will trigger the default action which is to print the current line.

A more "awk-ish" way to write smcameron's answer:

awk -v n=5 '1; NR % n == 0 {print ""}'

The "1;" is a condition that is always true, and will trigger the default action which is to print the current line.

answered Jun 11, 2009 at 16:04

A more "awk-ish" way to write smcameron's answer:

awk 'NR % 5 == 0 {print ""} 1' myfile

The trailing "1" is a condition that is always true, and will trigger the default action which is to print the current line.