date time comparison in php

Question

i have two time values as give below

$row2[0]=00:40:00; $row1[5]=14:00:00; $time=14:33:00 $time=$row[1];

i am combining $row2[0],$row1[5] like below

$secs = strtotime($row2[0])-strtotime("00:00:00"); $result = date("H:i:s",strtotime($row1[5])+$secs); $result=14:40:00

i use if condition as shown

if($row[1]>$row1[5] && $row[1]<$result) { $message=array("status"=>$result); } else { $message=array("status"=>''); }

but i get "status"=>"" its not correct

i want to get "status"=>"14:40:00"

please help us for getting correct out put

Niet the Dark Absol · Accepted Answer · 2012-05-12 18:36:56Z

You don't appear to define $row[1] anywhere, so it is treated as NULL, which as an integer is 0, which cannot be greater than the time you have given in $row1[5].

Try using less ambiguous variable names, it might make it easier to spot problems like this.

Personally I don't see why that if is there at all, just remove it and the else block, leaving just $message = array("status"=>$result);.

Sliq · Accepted Answer · 2012-05-12 18:36:26Z

is this real oder pseudo code ? because

$row2[0]=00:40:00;

is not real php code !

$row2[0] = 00:40:00; // $row2[0] would be 0, because you are assigning an integer $row2[0] = "00:40:00"; // $row2[0] would be "00:40:00", but as a string (!)

i would always work with timestamps btw.

sikas · Accepted Answer · 2012-05-12 18:40:42Z

I go with Panique on his answer, I want to add also:

You declared two vars:

$row2[0]=00:40:00; $row1[5]=14:00:00;

But you called different array elements in the if

if($row[1]>$row1[5] && $row[1]<$result)

Solve this and you should have your code working.

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