I have a plpgsql function in PostgreSQL 9.2 which returns a table. The function runs several SELECTs that return the same columns as the function and then either returns those results or raises an exception, depending on some checks. The only way I can see of doing this is with FOR ... LOOP, but I can't figure out a convenient way of returning the row.
I want to do something like this:
CREATE OR REPLACE FUNCTION my_function() RETURNS TABLE(column1 integer, column2 boolean, ...) AS $BODY$ DECLARE result_row RECORD; BEGIN FOR result_row IN (SELECT * FROM other_function_returning_same_columns()) LOOP IF something_wrong_with(result_row) THEN RAISE EXCEPTION 'Something went wrong'; END IF; RETURN NEXT result_row; END LOOP; END $BODY$ LANGUAGE plpgsql STABLE; This gives me an error:
ERROR: RETURN NEXT cannot have a parameter in function with OUT parameters
I'm not sure why Postgres is complaining here, because my code looks a lot like the example in the documentation, except that my function returns TABLE instead of SETOF. There are no OUT parameters.
I eventually managed to get it to work using:
RETURN QUERY SELECT result_row.column1, result_row.column2, ...; But having to list all the columns all the time is ugly and harder to maintain. I'm sure there must be a better way.