JSONException during AsyncTask

Question

@Override protected Integer doInBackground(Void... params) { String readMyJSON = readMyJSON(); try { JSONArray jsonArray = new JSONArray(readMyJSON); } catch (Exception e) { e.printStackTrace(); } return 0; }

This is not working, during JSONArray jsonArray = new JSONArray(readMyJSON);, JSONException occurs. Could somebody tell me where is the problem? Thanks in advance.

P.S.: Method I use:

 public String readMyJSON() { StringBuilder builder = new StringBuilder(); HttpClient client = new DefaultHttpClient(); HttpGet httpGet = new HttpGet("http://search.twitter.com/search.json?q=android"); try { HttpResponse response = client.execute(httpGet); StatusLine statusLine = response.getStatusLine(); int statusCode = statusLine.getStatusCode(); if (statusCode == 200) { HttpEntity entity = response.getEntity(); InputStream content = entity.getContent(); BufferedReader reader = new BufferedReader(new InputStreamReader(content)); String line; while ((line = reader.readLine()) != null) { builder.append(line); } } else { Log.e(ParseJSON.class.toString(), "Failed to download file"); } } catch (ClientProtocolException e) { e.printStackTrace(); } catch (IOException e) { e.printStackTrace(); } return builder.toString(); }

This method seems to be allright.

What do you get for output from readMyJSON()?

Neil Miller
– Neil Miller

2013-02-23 22:18:41 +00:00
Commented Feb 23, 2013 at 22:18 — Neil Miller
– Neil Miller, Commented Feb 23, 2013 at 22:18

Neil Miller · Accepted Answer · 2013-02-23 22:40:38Z

In short, the response from twitter is not an JSON array, so you get an exception. If you want the array of results, do the following:

JSONObject object = (JSONObject) new JSONTokener(json).nextValue(); JSONArray results = object.getJSONArray("results");

I suggest you read the Twitter API docs. Specifically, https://dev.twitter.com/docs/api/1/get/search.

I wanted to do this for the purpose of learning how to work with JSON. I used this search result only as an example. It seems that it´s working now, thanks.

A--C · Accepted Answer · 2013-02-23 22:28:52Z

0

Can you try this:

JSONArray jsonArray = new JSONArray("["+readMyJSON+"]");

I hope it should work.

edited Feb 23, 2013 at 22:28

A--C

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answered Feb 23, 2013 at 22:18

pallav_rus

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