I have an array like:
var abc = ["a","b","c"]; And the indexes are 0,1,2
Suppose, I want to delete the 2nd item "b" and I the indexes swipe!
Out put:
abc = ["a","c"] and the indexes are 0,1
How can I achieve this?
- Are the indexes always 0, 1, and 2?Qantas 94 Heavy– Qantas 94 Heavy2013-03-07 11:12:59 +00:00Commented Mar 7, 2013 at 11:12
- yes, always starts from 0Shahid Karimi– Shahid Karimi2013-03-07 11:14:30 +00:00Commented Mar 7, 2013 at 11:14
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4 Answers
Use the splice function :
abc.splice(1,1) // from index 1, removes 1 element Be careful that this changes the original array.
6 Comments
Shahid Karimi
No problem, can you bit explain the parameters?
Denys Séguret
I linked to the complete documentation. But here the first argument is the position and the second one the number of elements to remove.
Paul S.
+1 but would prefer wording the other way around (
from index 1, removes 1 element)Denys Séguret
@PaulS. Good idea. I edited (you could have to).
Denys Séguret
@PaulS. I just had a look. I'm not surprised to see you don't edit too much I see. But in this precise case I don't feel the need for the cloning addition, as "I like concise, easy-to-read questions and answers" :p
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Use splice(). E.g:
abc.splice(1, 1); would perform what you wanted in your example. abc[1] would now be "c".
Comments
You can use the array splice abc.splice(1,1);
Details: https://developer.mozilla.org/en-US/docs/JavaScript/Reference/Global_Objects/Array/splice
Comments
Have a look on it... I think this is what you want...
var arr = ["a","b","c"]; arr.splice(1,1); alert("["+arr.indexOf('a')+","+arr.indexOf('c')+"]"); 
