Given something like:
namespace :my_tasks do task :foo do do_something end task :bar do do_something_else end task :all => [:foo, :bar] end How do I make :all be the default task, so that running rake my_tasks will call it (instead of having to call rake my_tasks:all)?
Place it outside the namespace like this:
namespace :my_tasks do task :foo do do_something end task :bar do do_something_else end end task :all => ["my_tasks:foo", "my_tasks:bar"] Also... if your tasks require arguments then:
namespace :my_tasks do task :foo, :arg1, :arg2 do |t, args| do_something end task :bar, :arg1, :arg2 do |t, args| do_something_else end end task :my_tasks, :arg1, :arg2 do |t, args| Rake::Task["my_tasks:foo"].invoke( args.arg1, args.arg2 ) Rake::Task["my_tasks:bar"].invoke( args.arg1, args.arg2 ) end Notice how in the 2nd example you can call the task the same name as the namespace, ie 'my_tasks'
rake all. In this case, I have other namespaces, so what I want is to be able to call the task my_tasks:all as rake my_tasks, not as rake all.
Not very intuitive, but you can have a namespace and a task that have the same name, and that effectively gives you what you want. For instance
namespace :my_task do task :foo do do_foo end task :bar do do_bar end end task :my_task do Rake::Task['my_task:foo'].invoke Rake::Task['my_task:bar'].invoke end Now you can run commands like,
rake my_task:foo and
rake my_task 
task :my_task => ['my_task:foo', 'my_task:bar']I suggest you to use this if you have lots of tasks in the namespace.
task :my_tasks do Rake.application.in_namespace(:my_tasks){|namespace| namespace.tasks.each(&:invoke)} end And then you can run all tasks in the namespace by:
rake my_tasks With this, you don't need to worry to change your :all task when you add new tasks into that namespace.
x is of Rake::NameSpace class. I updated your answer to reflect this and be more explicit..each(&:invoke).I use this Rakefile for cucumber:
require 'cucumber' require 'cucumber/rake/task' namespace :features do Cucumber::Rake::Task.new(:fast) do |t| t.profile = 'fast' end Cucumber::Rake::Task.new(:slow) do |t| t.profile = 'slow' end task :ci => [:fast, :slow] end task :default => "features:ci" Then if I type just:
rake It runs the default task, which runs both fast and slow tests.
I learned this from Cheezy's blog.
The way I'm reading obvio171's question is that he is asking1) for a systematic way to invoke a certain task in a namespace by invoking the namespace as a task.
I've frequently encountered the same need. I like to logically group tasks into namespaces. Often that grouping resembles a hierarchy. Hence the desire to invoke the group makes very much sense to me.
Here's my take:
module Rake::DSL def group(name, &block) ns = namespace name, &block default = ns[:default] task name => "#{name}:default" if default ns end end group :foo do task :foo1 do |t| puts t.name end task :foo2 do |t| puts t.name end task :default => [:foo1, :foo2] end task :default => :foo 1)...or was asking, years ago. Nonetheless a still interesting question.
Add the following task outside of the namespace:
desc "Run all my tasks" task :my_tasks => ["my_tasks:all"] Keep in mind, that you can have a task with the same name as the namespace.
And hier a bigger example, that shows, how you can make use of tasks, which have the same name as the namespace, even when nesting namespaces:
namespace :job1 do task :do_something1 do puts "job1:do_something1" end task :do_something2 do puts "job1:do_something2" end task :all => [:do_something1, :do_something2] end desc "Job 1" task :job1 => ["job1:all"] # You do not need the "all"-task, but it might be handier to have one. namespace :job2 do task :do_something1 do puts "job2:do_something1" end task :do_something2 do puts "job2:do_something2" end end desc "Job 2" task :job2 => ["job2:do_something1", "job2:do_something2"] namespace :superjob do namespace :job1 do task :do_something1 do puts "superjob:job1:do_something1" end task :do_something2 do puts "superjob:job1:do_something2" end end desc "Job 1 in Superjob" task :job1 => ["job1:do_something1", "job1:do_something2"] namespace :job2 do task :do_something1 do puts "superjob:job2:do_something1" end task :do_something2 do puts "superjob:job2:do_something2" end end desc "Job 2 in Superjob" task :job2 => ["job2:do_something1", "job2:do_something2"] end desc "My Super Job" task :superjob => ["superjob:job1", "superjob:job2"] # Do them all just by calling "$ rake" task :default => [:job1, :job2, :superjob] Just copy it and try it out.
Based on Rocky's solution Default task for namespace in Rake
And this dexter's answer Is there a way to know the current rake task?
namespace :root do namespace :foo do end namespace :target do task :all do |task_all| Rake.application.in_namespace(task_all.scope.path) do |ns| ns.tasks.each { |task| task.invoke unless task.name == task_all.name } end end task :one do end task :another do end end end Combining Szymon Lipiński's and Shyam Habarakada's answers, here is what I think is the most idiomatic and consise answer:
namespace :my_tasks do task :foo do do_something end task :bar do do_something_else end end task :my_tasks => ["my_tasks:foo", "my_tasks:bar"] allows you to do rake my_tasks while avoiding cumbersome invocation of the subtasks.