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class Parent(db.Model): id = db.Column(db.Integer, primary_key = True) name = db.Column(db.String(120)) def __repr_(self): return '<Parent %r>' % (self.name) admin.add_view(ModelView(Parent, db.session)) class Child(db.Model): id = db.Column(db.Integer, primary_key = True) name = db.Column(db.String(120)) parent = db.Column(db.Integer, db.ForeignKey(Parent)) admin.add_view(ModelView(Child, db.session))

Hello -

The code above is an example of flask-admin page that I am trying to create. The goal is to have on Child's create page a text box for name and a drop down to select a parent.

With the above setup, there is only name field. The parent drop down box is missing.

Any ideas how to make it happen?

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4 Answers 4

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21

You likely need to specify some additional options to flask-admin via a subclass:

class ChildView(ModelView): column_display_pk = True # optional, but I like to see the IDs in the list column_hide_backrefs = False column_list = ('id', 'name', 'parent') admin.add_view(ChildView(Parent, db.session))
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Was looking for a way to display the PKs, perfect!
19

How about if you change the Child class to this:

class Child(db.Model): id = db.Column(db.Integer, primary_key = True) name = db.Column(db.String(120)) parent_id = db.Column(db.Integer, db.ForeignKey('parent.id')) parent = db.relationship('Parent', backref=db.backref('children', lazy='dynamic'))

I don't know much about this, and I don't know if you need the back reference, but this setup works for me with Flask-Admin.

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Awesome! I will try it tonight. Do I need any primaryjoin/secondaryjoin information? I've been getting a lot of errors about that. Hopefully your change will work awesomely!
Honestly, I wouldn't know. I've never seen anything about primaryjoin/secondaryjoin with Flask-Alchemy or Flask-Admin.
Reason why it works: Flask-Admin works with ORM objects, such as models, relations, etc. By default, Flask-Admin will ignore foreign keys in models as they just contain some number and Flask-Admin wants concrete ORM object to work with. So, when you have foreign key on the model, make sure you don't forget ORM level link between models - a relation. Flask-Admin will use this link to display related model(s). And no, you don't need to do fancy stuff or add backrefs to make it work.
4

Here is an all-inclusive solution that requires no manual maintenance.

from sqlalchemy import inspect class ChildView(ModelView): column_display_pk = True # optional, but I like to see the IDs in the list column_hide_backrefs = False column_list = [c_attr.key for c_attr in inspect(Child).mapper.column_attrs] admin.add_view(ChildView(Child, db.session))
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2

For what it is worth, none of the solutions listed here worked for me. I was facing the issue where foreign keys were not showing up in Flask-Admin.

This is what worked for them to show up: 

class CustomModelViewName(ModelView): can_delete = True column_hide_backrefs = False column_list = ["column_name", "column_name", "etc", "etc", "etc"] column_searchable_list = ["column_name"]
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