Get the real filepath of any file in Android

Question

I have an app which I can select an image from the device Gallery. I need to get the real filepath of the file to upload the file to a remote server. I have this working successfully with images only, but I wish to expand my app to include any filetype. My current code fails when trying to get the filepath of a non image. My code so far:

String filepath = ""; try { String[] projection = { MediaStore.Images.Media.DATA }; Cursor cursor = getContentResolver().query(uri, projection, null, null, null); if (cursor != null && cursor.getCount() != 0) { int column_index = cursor.getColumnIndex(MediaStore.Images.Media.DATA); cursor.moveToFirst(); filepath = cursor.getString(column_index); } } catch(Exception e) { Log.e("Path Error",e.toString()); }

I believe my problem lies with "MediaStore.Images.Media.DATA", but I am not sure what to replace it with to handle all file types.

UPDATE

OK, worked out that my code is 99% fine. It does work on multiple file types. The problem is with filenames which contain spaces. How do I handle this. I notice that the filepaths are url encoded ie spaces are replaced with "%20".

It needs to be able to handle any kind of file eg image/audio/video pdf docx etc etc ... — amburnside
– amburnside, Commented Dec 4, 2013 at 9:02
What is the error you get? Also any .DATA in MediaStore is just "_data" because they all inherit that from MediaColumns - that should not be your problem — zapl
– zapl, Commented Dec 4, 2013 at 9:24
You are correct it isn't that which is causing the app to crash, but it is not getting the filepath from uri: filepath returns a null value — amburnside
– amburnside, Commented Dec 4, 2013 at 9:48

amburnside · Accepted Answer · 2013-12-04 11:43:58Z

Turns out problem was handling filenames which contained URL encoded spaces i.e "%20"

For anyone that is interested my adapted code is as follows:

String filepath = ""; String uriPath = uri.toString(); // Handle local file and remove url encoding if(uriPath.startsWith("file://")) { filepath = uriPath.replace("file://",""); try { return URLDecoder.decode(filepath, "UTF-8"); } catch (UnsupportedEncodingException e) { e.printStackTrace() } } try { String[] projection = { MediaStore.Images.Media.DATA }; Cursor cursor = getContentResolver().query(uri, projection, null, null, null); if (cursor != null && cursor.getCount() != 0) { int column_index = cursor.getColumnIndex(MediaStore.Images.Media.DATA); cursor.moveToFirst(); filepath = cursor.getString(column_index); } } catch(Exception e) { Log.e("Path Error",e.toString()); } return filepath;

Kishan Vaghela · Accepted Answer · 2014-12-02 11:05:55Z

1

Uri fileUri=Uri.fromfile(fileObject); USE: setUrl(Uri.decode(fileUri));

answered Dec 2, 2014 at 11:05

Kishan Vaghela

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