here is my code:
def is_prime(x): if x < 2: return False else: for i in range(2,x): if x % i == 0: return False else: return True print is_prime(508) I don't understand why the last else: return true works with the indentation. If I type
else: for i in range(2,x): if x % i == 0: return False else: return True Then def is_prime(2) returns none? why?
Because in python, a for-loop can have an else-clause.
This clause is executed if the loop exits normally. If the loop is exited by using the break statement, the else is not entered.
I suggest you read up the official doc and if it's still unclear, this blog summarizes the concept fairly well.
for and while loops also know else clauses, not just if or try statements.
The else clause of a loop is executed when control leaves the loop, unless you have used break to abort the loop.
I must admit that this behavior puzzled me at first, as well, but it's actually quite sensible, and a useful feature (see this answer for a good example).
In the second example, the else is on the same indentation level as the if, so they both belong together. So for the first item in the loop, you will either return False or True depending on that value; i.e. the loop won’t continue.
Now in your original code, the else is on the same level as the for. So it’s a for..else which is actually a special construct:
When the items are exhausted, the suite in the
elseclause, if present, is executed, and the loop terminates.
So basically, the else block is executed, if the loop naturally finishes (without calling break). So in your case, it’s the same as leaving the else out:
for i in range(2,x): if x % i == 0: return False return True As others have said, a for loop can have an else clause. Read more in the docs
When used with a loop, the else clause has more in common with the else clause of a try statement than it does that of if statements: a try statement’s else clause runs when no exception occurs, and a loop’s else clause runs when no break occurs.
