I have a list of values that looks something like this:
["Some", "random", "values", [], "in", "a", [], "list"]. I would like to create a new list with the empty list items removed. Like this:
["Some", "random", "values", "in", "a", "list"]. What is the easiest way of going about this? I assume using list comprehensions to build a new list is going to be the most efficient way of doing this. How would I filter this list using list comprehensions?
List comprehensions are a neater lists:filter/2:
[E || E <- List, E /= []] This can be achieved using lists:filter.
List = ["Some", "random", "values", [], "in", "a", [], "list"], lists:filter(fun(X) -> X /= [] end, List). lists:filter takes a fun and a list. The fun should take a list item and return true or false. If the fun returns true the item is returned in the new list.
More information can be found here: http://erlangcentral.org/wiki/index.php?title=Filtering_Lists