Get domain name from URL without java.net in Java

Question

I would like to know in GWT is there an easy way to get host name from url WITHOUT java.net.*; Since client side doesn't support this package.

Input ejw.example.com/anotherexample?fun=no output example.com Input https://www3.example.com/yeteagainanotherexample?fun=miserable output example.com

ejw.example.com, www3.example.com and example.com are all different domain names. — Andrei Volgin
– Andrei Volgin, Commented Jun 20, 2014 at 20:00
I meant host. And I am looking for a built-in method if it exist. — wtsang02
– wtsang02, Commented Jun 20, 2014 at 20:04
They are different host names as well :), because they can - and often do - resolve to different IP addresses. What you look for in your examples is a second-level domain name, but you have to make sure that this is really what you need. — Andrei Volgin
– Andrei Volgin, Commented Jun 20, 2014 at 20:05
Correct. 2nd level domain name. I would write my own method but if there was a built-in class that replaces java.net that would be great. — wtsang02
– wtsang02, Commented Jun 20, 2014 at 20:13
You may find an answer to this question very helpful: stackoverflow.com/questions/4452916/… — Andrei Volgin
– Andrei Volgin, Commented Jun 20, 2014 at 20:50

Anubian Noob · Accepted Answer · 2015-04-17 00:28:40Z

1

com.google.gwt.user.client.Window.Location.getHost()

edited Apr 17, 2015 at 0:28

Anubian Noob

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answered Apr 16, 2015 at 23:49

DevMo

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Comments

Community · Accepted Answer · 2017-05-23 11:43:37Z

Try with com.google.gwt.regexp.shared.RegExp that is used for regular expressions with features like Javascript's RegExp, plus Javascript String's replace and split methods (which can take a RegExp parameter).

Try below regex that captures all the everything between first dot and first forward slash and get it at match index 1.

https*://\w+\.(.*?)/

Here is demo on debuggex and regexr

Sample code:

String url="https://www3.example.com/yeteagainanotherexample?fun=miserable"; System.out.println(RegExp.compile("https*://\\w+\\.(.*?)/").exec(url).getGroup(1));

Note: I am not good in regex so please change the regex pattern as per your need. Read more about

Why do you think he needs his own domain name? I think the OP is talking about URLs in general.
And you did not provide the second-level domain name that the OP is looking for.
What about blog.inside.example.co.uk? Your regex fails. There can be up to 127 dots in domain name.
@AndreiVolgin Sorry I have very little knowledge about URL domain name. It's just a example. The regex can be modified or simply use String#split() method.
String.splt() is also not trivial, because you need to distinguish between blog.example.com and `blog.example.com.me" - just to make up an example.

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