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I need to sort string, and I came up with the following function.

 def mysort(comb_): str = [] size = len(comb_) for c in comb_: str.append(c) str.sort() return ''.join(str)

Is there any way to make it compact?

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4 Answers 4

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22 
return ''.join(sorted(comb_))
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This is the correct answer. It cannot get more succinct (or idiomatic) than that. Disregarding the strange underscore in the variable name, of course.
3 
def sortstr(comb_): return ''.join(sorted(comb_))

e:f;b :(

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2

If you want to get a string back do this:

def sort_string(string): return "".join(sorted(string))

But if you want a list back, do this:

def sort_string(string): return sorted(string)
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1 
def sort_string(s): def sort_string_to_a_list(s): return sorted(s, lambda x,y: cmp(x.lower(), y.lower()) or cmp(x,y)) sorted_list = sort_string_to_a_list(s) return ''.join(sorted_list)
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