Incrementing a string

Question

How do I take an input and increment each letter by one e.g "ABC" to "BCD" in Java. I have attempted below to try and change the string to an int and then increase the value by 1.

import java.util.Scanner; public class w7q3 { public static void main(String[] args) { Scanner in = new Scanner (System.in); String str =""; int A = 0; System.out.println ("Enter String"); str = in.nextLine(); int num = Integer.parseInt(str); num= num +1; System.out.println(str); } }

What happens if the letters are not consecutive, such as "ADT"? What happens if one of the letters is "Z"? — Bobulous
– Bobulous, Commented Dec 24, 2014 at 0:55
I guess you'd get some random ASCII garbage. Sounds like a homework question tbh, but no clue who'd do homework on Christmas. — MightyPork
– MightyPork, Commented Dec 24, 2014 at 1:10
@Arkanon Wouldn't the first one just produce "BEU"? I didn't see anything ambiguous about that part of the requirements. — ajb
– ajb, Commented Dec 24, 2014 at 1:29

Elliott Frisch · Accepted Answer · 2014-12-24 01:14:05Z

Loop over every char in the String, add one to the char and cast it back to a char append that to a StringBuilder. Something like,

Scanner in = new Scanner(System.in); System.out.println("Enter String"); String str = in.nextLine(); StringBuilder sb = new StringBuilder(); for (char ch : str.toCharArray()) { sb.append((char) (ch + 1)); } System.out.println(sb.toString());

Of course, if you want to handle wrap-around you could do something like

for (char ch : str.toCharArray()) { char o = ((char) (ch + 1)); if (Character.isDigit(ch)) { if (o > '9') { o = '0'; } } else if (Character.isLowerCase(ch)) { if (o > 'z') { o = 'a'; } } else if (Character.isUpperCase(ch)) { if (o > 'Z') { o = 'A'; } } sb.append(o); }

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