Looping over pairs of values in bash

Simplest so far:

for i in "1 a" "2 b" "3 c"; do a=( $i ); echo "${a[1]}"; echo "${a[0]}"; done a 1 b 2 c 3 

You can use an associative array:

animals=(dog cat mouse) declare -A size=( [dog]=big [cat]=medium [mouse]=small ) declare -A sound=( [dog]=barks [cat]=purrs [mouse]=cheeps ) for animal in "${animals[@]}"; do echo "$animal is ${size[$animal]} and it ${sound[$animal]}" done 

This allows you traversing pairs, triples, etc. Credits: the original idea is taken from @CharlesDuffy-s answer.

If you want to use one variable and perform and action with it, you just need to use one loop:

for file in 4 5 6 7 8 do paste "${file}_1" "${file}_2" done 

This will do

paste 4_1 4_2 paste 5_1 5_2 ... 

the above did not work for me, but the following does read values in pairs from an ordered list

(can be more than pairs adding extra 'read-lines' :-)

while read x; do read y echo "$x $y" done << '___HERE' X1 Y1 X2 Y2 X3 Y3 ___HERE 

produces

X1 Y1 X2 Y2 X3 Y3 

There is a common pattern where you have pairs of files, where one name of the pair can be easily derived from the other. If the file you know the name of is X and the other file is Y, you have the following common use cases.

• For renaming, Y is X with an extension removed and/or a date stamp added.
• For transcoding, Y is X with a different extension and perhaps a different directory.
• For many data analysis tasks, X and Y share some parts of the file name, but have different parameters or extensions.

All of these lend themselves to the same rough code skeleton.

for x in path/to/base*.ext; do dir=${x%/*} # Trim trailing file name, keep dir base=${x##*/} # Trim any leading directory # In this case, $y has a different subdirectory and a different extension y=${dir%/to}/from/${base%.ext}.newext # Maybe check if y exists? Or doesn't exist? if [ -e "$y" ]; then echo "$0: $y already exists -- skipping" >&2 continue fi mv or ffmpeg or awk or whatever "$x" and "$y" done 

The key here is the observation that y can be derived from x with some simple variable substitutions. So you loop over the x values, and figure out the corresponding y value inside the loop.

Here, we have used the shell's built-in ${variable#prefix} and ${variable%suffix} operators to return the variable's value with any leading prefix or trailing suffix, respectively, trimmed off. (There is also ## and %% to match the longest, instead of the shortest, possible match. The expression after # or % is a regular shell glob pattern.) These should usually be all you need, although you frequently see sed or awk scripts even for this trivial job (where really you should usually try to avoid an external process), as well as of course for more demanding transformations.

If you need to loop over x files scattered across different directories, maybe the loop should start with something like

 find dir1 dir2 etc/and/so/forth -type f -name 'x-files*.ext' -print | while IFS='' read -r x; do : 

A commonly seen problem in similar questions is answers which fail to quote $x and $y correctly. Generally, any variable containing a file name should always be in double quotes.

Where X and Y are unrelated, a common solution is to loop over a here document containing the mapping:

while read -r x y; do : stuff with "$x" and "$y" done <<'____HERE' first_x_value first_y_value another_x corresponding_y random surprise ____HERE 

It is often convenient to use a while/read loop to do this sort of thing:

#!/bin/sh while read i j; do echo i=${i} j=${j} done << EOF 4_1 4_2 5_1 5_2 6_1 6_2 7_1 7_2 8_1 8_2 EOF