Undeclared Identifier although it is declared

Question

for a program in which I try to create a file and later write into it, I have written the following:

 int main(){ ... .... (some code) .... char DataBuffer[] = "This is the test file"; ... ... }

I get the error "DataBuffer: undeclared identifier" . I am using Microsoft Visual C++ Express. And in an old asked question here in stackoverflow.com, I have read that Visual C++ uses an old C89 standard and that it does not support C99 standard. For that reason, I must declare the variables at the beginning(which I did for the rest of the parameters of CreateFile() and WriteFile). I mean, when you consider the following:

 DWORD dwCreationDisposition = CREATE_NEW;

Then I split it up and changed it to:

 DWORD dwCreationDisposition; ... dwCreationDisposition = CREATE_NEW

but I do not know how I should do it with an array. So, for example when I write:

 char DataBuffer[]; .... DataBuffer[] = = "This is the test file";

Then I also get the same error message. What can I do ? Is there any possibility to change the compiler options ? Or a chance to rewrite it such that the integrated compiler accepts it as the other splitted variables/parameters ?

best regards,

You should be able to declare an init the variables in one statement still, albeit at the beginning of the scope. That said, you can also open a new scope using {} in order to declare a new variable there. Note that what @Mint97 suggests is different, because it declares a pointer to non-constant data which you still may not modify, while the original code declared a mutable array of chars. — Ulrich Eckhardt
– Ulrich Eckhardt, Commented Mar 14, 2015 at 10:38
"Undeclared Identifier although it is identified" Did you mean "Undeclared Identifier although it is declared?" — Spikatrix
– Spikatrix, Commented Mar 14, 2015 at 10:45

Vagish · Accepted Answer · 2015-03-14 10:38:32Z

If you want your string to be re-writable you should so this:

 char DataBuffer[MAX_SIZE]; .... strcpy(DataBuffer,"This is the test file");

Also consider using strncpy for avoiding buffer overrun error.

If your string is constant then:

const char DataBuffer[] = "This is the test file";

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