morelinq distinct by multiple properties

Question

I have been using morelinq to create a distinct list of objects. My objects have about 20 properties, none of which will be unique in the final list. However 2 properties used together can reveal the unique objects:

Parent Id | Child Id

1 | 1
1 | 2
2 | 1
2 | 2
2 | 3

I saw this question and thought it was the same problem so I downloaded morelinq and tried using:

list = list.DistinctBy(c => new { c.id, c.parentid }).ToList();

However this results in a distinct list on EITHER property, not both (so I'd only ever see one child per parent)

What is the correct way to use morelinq to achieve this?

Use Groupby instead.

BLoB
– BLoB

2015-05-06 10:23:04 +00:00
Commented May 6, 2015 at 10:23 — BLoB
– BLoB, Commented May 6, 2015 at 10:23

Vishwajeet Bose · Accepted Answer · 2015-05-06 10:25:11Z

5

 list = list .GroupBy(a=> new { a.id, a.parentid}) .Select(a=> a.first());

answered May 6, 2015 at 10:25

Vishwajeet Bose

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