django for loop random order determine

Question

I want to have a tag list of 10 main tags but displayed in random order because the font weight will determine their weight.

first i order objects and get 10 tags, than I use shuffle to randomise the order. So far it works. My issue now is to use {{forloop.counter0}} in template which outputs below code in random order:

 <tr> <td class="tag-0">Tag3</td> </tr> <tr> <td class="tag-1">Tag1</td> </tr> <tr> <td class="tag-2">Tag2</td> </tr>

Instead I want it to be like this:

<tr> <td class="tag-2">Tag3</td> </tr> <tr> <td class="tag-0">Tag1</td> </tr> <tr> <td class="tag-1">Tag2</td> </tr>

template:

{% for t in tags %} <tr> <td class="tag-{{forloop.counter0}}">{{t.title}}</td> </tr> {% endfor %}

in views:

tags = list(Model.objects.order_by('title')[:10]) random.shuffle(tags)

jape · Accepted Answer · 2015-08-25 19:05:16Z

I would create a model manager to do your initial filtering, and then randomize the order of the objects in your view. You want to try to take a "fat" model, "thin" view approach. The more you can do in your model, the easier changes will be down the road. For example,

models.py:

class FooManager(models.Manager): def get_titles(self): return super(FooManager, self).get_queryset.order_by('title') class Foo(models.Model): title = models.CharField(max_length=120) objects = FooManager() def __unicode__(self): return self.title

views.py:

def view(request): get_titles = Foo.objects.get_titles()[:10] titles = list(get_titles) random.shuffle(titles) context = { 'titles': titles } return render(request, 'template.html', context)

Your templates become a lot easier, too.

html:

{% for t in titles %} {{ t.title }} {% endfor %}

I hope that helps! Good luck!

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