How to update a modelForm in Django with Ajax

Question

I would like to update a template with Ajax.

My problem is:

I select a client in a list on the form and display only the corresponding data in an another list on the same page in a second list
At this time, I can not update my template with protocols corresponding to the client
In my views, I try to create a list with a queryset (it works) but I cannot update my template with the new list
I retrieve the selected client but when I post with render_to_request it does not update the template
Is there any possibility to do that and how can I update my list with the ajax part of the program.

Community · Accepted Answer · 2017-05-23 11:44:25Z

You can use something like this:

(based on https://stackoverflow.com/a/21762215/5244995)

second_list.tmpl (template)

{% for value in corresponding_data %} <li>{{ value }} (replace with your own templating)</li> {% endfor %}

views.py

def update_second_list(request, ob_id): # (get the data here) return render('second_list.tmpl', {'corresponding_data': ...}

JS script on main page (uses jQuery)

$.ajax({url:"", dataType:"text", success: function(html) { var newDoc = $.parseHTML(html, document, false); // false to prevent scripts from being parsed. var secondList = $(newDoc).filter(".secondList").add($(newDoc).find(".secondList")); $(".secondList").replaceWith(secondList); // only replace second list. // other processing }});

var secondList = $(newdoc).filter(".secondList").add($(newdoc)).find(".secondList)); TOKEN ILLEGAL Could you help me please

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How to update a modelForm in Django with Ajax

1 Answer 1

second_list.tmpl (template)

views.py

JS script on main page (uses jQuery)

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Collectives™ on Stack Overflow

1 Answer 1

second_list.tmpl (template)

views.py

JS script on main page (uses jQuery)

4 Comments

Linked

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