Regular expression to extract hashes from file

Question

I have a file in this format:

5:Name: {"hash":"c602720140e907d715a9b90da493036f","start":"2016-02-20","end":"2016-03-04"} 5:Name: {"hash":"e319b125d71c62ffd3714b9b679d0624","sa_forum":"on","start":"2015-11-14","end":"2016-02-20"}

I am trying to extract the hash key and date using a regular expression. How can I do it?

I tried this /^[a-z0-9]{32}$/ for the hash but it doesn't work.

I would appreciate some help.

Edit: This is a text file, and I'm trying to preg_match() it. Here's my code:

$file = file_get_contents("log.txt"); preg_match("/^[a-z0-9]{32}$/",$file, $hashes); var_dump($hashes);

I get an empty array.

looks like it's a json...decode it: json_deocde($string,true); — ka_lin
– ka_lin, Commented Feb 20, 2016 at 22:46

Will · Accepted Answer · 2016-02-20 22:53:16Z

The problem is that you're bounding your match with ^ and $, but you actually want to match something in the middle of the string. Try this:

/(?<=")[a-f0-9]{32}(?=")/

This will only match between the quotes. Also, you don't need a-z as it can only be a-f.

Also, since you want an array of all of the hashes in the file and not just one, you need preg_match_all():

php > $file = file_get_contents("hashfile.txt"); php > preg_match_all('/(?<=")[a-f0-9]{32}(?=")/', $file, $matches); php > var_dump($matches); array(1) { [0]=> array(2) { [0]=> string(32) "c602720140e907d715a9b90da493036f" [1]=> string(32) "e319b125d71c62ffd3714b9b679d0624" } } php >

The matches are stored in the array $matches[0] in my above example.

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