Pattern matcher is not giving expected output

Question

I have the below code.

String testdata = "%%%variable1%%% is not equal to %%%variable2%%%"; Pattern p = Pattern.compile("\\%%%(.*?)\\%%%"); Matcher m = p.matcher(testdata); String variables = ""; int i = 0; while (m.find()) { System.out.println(m.group()); variables=m.group().replaceAll("%%%", ""); System.out.println(variables); i++; }

I am trying to print the string inside two %%%. So I am expecting below output:

%%%variable1%%% variable1 %%%variable2%%% variable2

But the actual output is:

%%%variable1%%% variable1 variable2 variable2

Why is it so? What is the problem with this?

Had there been one more variable, there would have been error.. — rock321987
– rock321987, Commented Apr 26, 2016 at 7:05

rock321987 · Accepted Answer · 2016-04-26 06:59:02Z

You need to remove i. There is no need of it

while (m.find()) { System.out.println(m.group()); String variables=m.group().replaceAll("%%%", ""); System.out.println(variables); }

Ideone Demo

You don't also need replaceAll because what you require is already in first capturing group

while (m.find()) { System.out.println(m.group()); System.out.println(m.group(1)); }

Ideone Demo

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